Expanding and simplifying
Two linear expressions can be expanded, and then simplified by collecting like , if there are any.
Linear expressions have no with power of 2 or higher.
For example,
15x – 4y is a linear expression but 15x – 4y² is not.
Expanding and simplifying two linear expressions
Two linear expressions can be multiplied together by separating the in the first bracket and then multiplying each in turn by the in the second bracket.The expanded expression can then be simplified by collecting like .
Example
Expand the brackets and simplify fully \((p+ 3q)(3p – 5q)\)
Solution
This time there are in ‘p’ and in ‘q’ with no stand-alone numbers, but the method is exactly the same.
\(\mathbf{p(3p - 5q) + 3q(3p - 5q)} = {3p^2- 5qp} +9qp - 15q^2{+ 3x - 12}\)
that p x -5q = -5pq or -5qp
The order of the letters does not matter but the number always comes first.
\(3p^2 {- 5qp + 9qp} - 15q^2 = 3p^2 + 4qp - 15q^2\)
Answer
\((p+ 3q)(3p – 5q) = 3p^2 + 4qp - 15q^2\)
Example
Expand and simplify \((2x - 3)(3x - 5)\)
Solution
Separate the ‘2x’ and the ‘-3’ from the first bracket and multiply each by (3x - 5)
\(\mathbf {(2x -3)(3x - 5) = 2x (3x - 5) + 3 (3x - 5)}\)
Expand the brackets
\(\mathbf {{2x (3x - 5)}{- 3 (3x - 5)} = {6x^2- 10x }{- 9x - 12}}\)
Be careful with signs when multiplying out the second bracket!
Now collect like
\(6x^2 {- 10x + 9x} +15 = 6x^2 {-19x} + 15 \)
Answer
\((2x - 3)(3x - 5) = 6x^2 – 19x + 15\)
Example
Expand the brackets and simplify fully \((p+ 3q)(3p – 5q)\)
Solution
This time there are in ‘p’ and in ‘q’ with no stand-alone numbers, but the method is exactly the same.
\(\mathbf {p(3p - 5q) {+ 3q(3p - 5q)} = {3p^2- 5qp} +9qp - 15q^2 {+ 3x - 12}}\)
that p x -5q = -5pq or -5qp
The order of the letters does not matter but the number always comes first.
\(3p^2 {- 5qp + 9qp} - 15q^2 = 3p^2 + 4qp - 15q^2\)
Answer
\((p+ 3q)(3p – 5q) = 3p^2 + 4qp - 15q^2\)
Alternative FOIL method
An alternative method is the FOIL method. It can be quicker especially if you are confident with + and – numbers.
FOIL stands for
- First - Multiply the first in the brackets
- Outside - Multiply the outside
- Inside - Multiply the inside
- Last - Multiply the last
- Now collect like
\(10x^2 {- 2x + 15x} - 3 = 10x^2 {+ 13x} - 3\)
Answer
\((x + 3)(x - 4) = 10x^2 + 13x – 3\)
Question
Expand the brackets and simplify this expression
(2y – 7)(4y + 1)
Method 1
\((2y – 7)(4y + 1) = 2y(4y + 1) -7(4y + 1)\)
\(= 8y^2 + 2y -28y – 7\)
Collect like
\(= 8y^2 - 26y – 7\)
Answer
\((2y – 7)(4y + 1) = 8y^2 -26y – 7\)
Method 2 - FOIL
Collect like
\(8y^2 + \mathbf{2y -28y} – 7 = 8y^2 \mathbf{-26y} – 7\)
Answer
\((2y – 7)(4y + 1) = 8y^2 -26y – 7\)
Test yourself
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